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Andrea

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IMPs correction ( 09:54:59 MonApr 28 2003 )

Country: Italy

Hi all,

I have some trouble to undertand the way to correct the split scores and the penalties playing IMPs.

for example:

Team A has 23 IPMs and team B has 6 IMPs without two boards.

In the first of them the TD has asigned a split:

open room Team A: -140
open room Team B: 200
Close room: team A: -140

On the second board the TD has asigned a Adj. score to team A of the 60 % and Team B of 50 %. On the close room the result was: -140 for Team A.

Please, help me


  
bluejak

427 posts
Forum Host

Reply
Re: IMPs correction ( 16:22:28 MonApr 28 2003 )

Assuming I have understood what has happened {if I am wrong correct me and I shall try again :smile:}

On the first board:

Team A: -140 -140 = -280 = -7 imps
Team B: +200 +140 = +340 = +8 imps

On the second board:

Team A: Average plus = +3 imps
Team B: Average = 0 imps
Note that the score in the other room is ignored once the Director gives Average and Average Plus. That is why it is far better to assign real scores, and a Director should always do so if the board was played at all. I assume here the board was unable to be played.


Now, there are two possibilities. Either this knockout teams, or it is some other teams like a congress round robin or a league.

First, assume it is not knockout teams

Team A scored +23 -6 -7 +3 = +13
Team B scored -23 +6 +8 +0 = -9

It does not matter that these two scores do not agree. That is never necessary except in knockout teams, so now let us assume it is knockout teams.

In knockout teams you average the scores on each board if they are different. So the first board is scored as

(-7 -8)/2 for Team A, ie -7.5 imps.

The second board is scored as

(+3 +0)/2 for Team A, ie +1.5 imps.

In each case Team B gets the reverse.

So if this was knockout,
Team A scored +23 -6 -7.5 +1.5 = +11

So Team A beat Team B by 11 imps.












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David Stevenson <laws2@blakjak.com>
Liverpool, England, UK
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